this is about databases questions , maybe i miss copy some option D, if ABC there are all incorrecct please type D after that question thank you
Suppose that a PRODUCT table contains two attributes, PROD_CODE and VEND_CODE. Those two attributes have values of ABC, 125, DEF, 124, GHI, 124, and JKL, 123, respectively. The VENDOR table contains a single attribute, VEND_CODE, with values 123, 124, 125, and 126, respectively. (The VEND_CODE attribute in the PRODUCT table is a foreign key to the VEND_CODE in the VENDOR table.) Given that information, what would be the query output for a INTERSECT query based on these two tables?
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a. The query output will be: 125,124,123,126 |
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b. The query output will be: 123 |
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c. The query output will be: 125,124,124,123,123,124,125,126 |
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d. The query output will be: 123,124,125 |
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What is the difference between UNION and UNION ALL?
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a. A UNION ALL operator will yield all rows of both relations, including duplicates |
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b. UNION yields unique rows |
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c. UNION eliminates duplicates rows |
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d. All of these choices are correct. |
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A(n) ______________ is a block of PL/SQL code that is automatically invoked by the DBMS upon the occurrence of a data manipulation event (INSERT, UPDATE or DELETE.)
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a. stored procedure |
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__________________ means that the relations yield attributes with identical names and compatible data types.
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b. Set comparable |
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c. Union compatible |
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d. compatible-oriented
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Which of the following a parts of the definition of a trigger?
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a. The triggering level |
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b. The triggering action |
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c. The triggering timing |
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d. All of these choices are correct. |
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Which of the following relational set operators does NOT require that the relations are union-compatible?
Suppose that you have two tables, EMPLOYEE and EMPLOYEE_1. The EMPLOYEE table contains the records for three employees: Alice Cordoza, John Cretchakov, and Anne McDonald. The EMPLOYEE_1 table contains the records for employees John Cretchakov and Mary Chen. Given that information, what is the query output for the INTERSECT query?
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a. The query output will be: John Cretchakov and Mary Chen |
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b. The query output will be: Alice Cordoza, John Cretchakov, Anne McDonald and Mary Chen |
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c. The query output will be: John Cretchakov |
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d. The query output will be: Alice Cordoza, John Cretchakov, Anne McDonald, John Cretchakov and Mary Chen |
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A _____________________ is a join that performs a relational product (or Cartesian product) of two tables.
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b. DUPLICATE JOIN |
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What Oracle function should you use to calculate the number of days between the current date and January 25, 1999?
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a. SELECT SYSDATE()-#25-JAN-1999#; |
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b. SELECT SYSDATE – TO_DATE(’25-JAN-1999′, ‘DD-MON-YYYY’) FROM DUAL; |
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c. SELECT SYSDATE FROM DUAL; |
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d. SELECT SYSDATE()-JAN-#25-1999#; |
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Using tables named T1 and T2, write a query example for a LEFT OUTER JOIN, assuming that T1 and T2 share a common column named C1.
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a. SELECT * FROM T1 OUTER JOIN T2 ON T1.C1 = T2.C2; |
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b. SELECT * FROM T1 JOIN T2 ON T2.C1 = T2.C1; |
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c. SELECT * FROM T1 LEFT JOIN T2 ON T1.C1 = T2.C1; |
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d. SELECT * FROM T1 LEFT OUTER JOIN T2 ON T1.C1 = T2.C1; |
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Suppose that you have two tables, EMPLOYEE and EMPLOYEE_1. The EMPLOYEE table contains the records for three employees: Alice Cordoza, John Cretchakov, and Anne McDonald. The EMPLOYEE_1 table contains the records for employees John Cretchakov and Mary Chen. Given that information, what is the query output for the MINUS query (specifically, SELECT * FROM EMPLOYEE MINUS SELECT * FROM EMPLOYEE_1)?
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a. The query output will be: Alice Cordoza, John Cretchakov, Anne McDonald and Mary Chen |
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b. The query output will be: Alice Cordoza, John Cretchakov, Anne McDonald, John Cretchakov and Mary Chen |
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c. The query output will be: Mary Chen |
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d. The query output will be: Alice Cordoza and Anne McDonald |
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What Oracle function should you use to return the current date?
Suppose that a PRODUCT table contains two attributes, PROD_CODE and VEND_CODE. Those two attributes have values of ABC, 125, DEF, 124, GHI, 124, and JKL, 123, respectively. The VENDOR table contains a single attribute, VEND_CODE, with values 123, 124, 125, and 126, respectively. (The VEND_CODE attribute in the PRODUCT table is a foreign key to the VEND_CODE in the VENDOR table.) Given that information, what would be the query output for a UNION ALL query based on these two tables?
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a. The query output will be: 125,124,124,123,123,124,125,126 |
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b. The query output will be: 125,124,124,123 |
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c. The query output will be: 125,124,123,126 |
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d. The query output will be: 123 |
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_________________is a term used to refer to SQL statements that are contained within an application programming language such as COBOL, C++, ASP, Java, or ColdFusion.
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b. Embedded SQL |
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The order of the operands (tables) matter in a _______ query.
Which of the following is true of Oracle sequences?
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a. You can have as many sequences as you want and they are not tied to any particular table. |
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b. A sequence is a completely independent object. |
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c. The sequence-generated value is not tied to any field in any table and can, therefore, be used on any attribute in any table. |
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Which of the following is true of Oracle sequences?
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a. You can have as many sequences as you want and they are not tied to any particular table. |
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b. A sequence is a completely independent object. |
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c. The sequence-generated value is not tied to any field in any table and can, therefore, be used on any attribute in any table. |
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d. All of these choices are correct. |
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A(n) ______________ is a named collection of procedural and SQL statements that are stored in the database and that can be used to encapsulate and represent business transactions.
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b. stored procedure |
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Suppose that you have two tables, EMPLOYEE and EMPLOYEE_1. The EMPLOYEE table contains the records for three employees: Alice Cordoza, John Cretchakov, and Anne McDonald. The EMPLOYEE_1 table contains the records for employees John Cretchakov and Mary Chen. Given that information, what is the query output for the UNION query?
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a. The query output will be: Alice Cordoza, John Cretchakov, Anne McDonald and Mary Chen |
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b. The query output will be: John Cretchakov and Mary Chen |
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c. The query output will be: Alice Cordoza, John Cretchakov, Anne McDonald, John Cretchakov and Mary Chen |
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d. The query output will be: John Cretchakov
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A subquery can appear in which of the following places in a SQL statement?
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a. as part of a FROM clause, |
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b. to the right of a HAVING clause conditional operator, |
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c. in a EXISTS operator, |
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d. All of these choices are correct. |
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A __________ is a query (expressed as a SELECT statement) that is located inside another query and is normally executed first.
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c. outside query |
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d. special query |
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What string function (in Oracle) should you use to list the first three characters of a company’s EMP_LNAME values using a table named EMPLOYEE?
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a. SELECT STR(EMP_LNAME, 1, 3) FROM EMPLOYEE; |
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b. SELECT STRING(EMP_LNAME, 1, 3) FROM EMPLOYEE; |
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c. SELECT SUBSTRING(EMP_LNAME, 1, 3) FROM EMPLOYEE; |
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d. SELECT SUBSTR(EMP_LNAME, 1, 3) FROM EMPLOYEE; |
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_____________ is a term used to describe an environment in which the SQL statement is not known in advance; instead, the SQL statement is generated at run time.
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b. Embedded SQL |
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Suppose that a PRODUCT table contains two attributes, PROD_CODE and VEND_CODE. Those two attributes have values of ABC, 125, DEF, 124, GHI, 124, and JKL, 123, respectively. The VENDOR table contains a single attribute, VEND_CODE, with values 123, 124, 125, and 126, respectively. (The VEND_CODE attribute in the PRODUCT table is a foreign key to the VEND_CODE in the VENDOR table.) Given that information, what would be the query output for a MINUS query (VENDOR MINUS PRODUCT) based on these two tables?
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a. The query output will be: 124 |
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b. The query output will be: 125,124,123,126 |
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c. The query output will be: NULL |
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d. The query output will be: 126
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In the relational model, SQL operators are ________________ because they operate over entire sets of rows and columns (or tables) at once.
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a. set-oriented |
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b. table-oriented |
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c. completeness-oriented |
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Which of the followings explains the difference between a regular subquery and a correlated subquery?
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a. A correlated subquery will execute once for each row evaluated by the outer query |
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b. A regular subquery executes only once and the result is held for use by the outer query |
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c. A regular subquery executes before the outer query |
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d. All of these choices are correct. |
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If you do not specify a join condition when joining tables, the result will be a ______________ or PRODUCT operation.
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b. DUPLICATE JOIN |
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A ______________ is a subquery that executes once for each row in the outer query; it will run the outer query first, and then it will run the inner subquery once for each row returned in the outer subquery.
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a. outside subquery |
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b. uncorrelated subquery |
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c. correlated subquery |
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A relational view has which of the following characteristics?
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a. views are dynamically updated |
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b. views may be used as the basis for reports or queries, just like tables |
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c. views provide a level of security in the database |
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A(n) ______________ is a special type of object that generates unique numeric values in ascending or descending order; it can be used to assign values to a primary key field in a table and it provides functionality similar to the Autonumber data type in MS Access.
which of the following is NOT considered an advantage of a stored procedure?
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a. Increase performance |
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b. Help reduce code duplication through code isolation and code sharing |
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c. Reduce network traffic |
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d. None of these choices are correct. |
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What are the types of results a subquery can return?
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a. a list of values only |
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b. a single value, a list of values, or a virtual table |
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c. a single value only |
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d. a virtual table only
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The SQL standard prescribes three different types of __________ operations: LEFT, RIGHT, and FULL.
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c. DUPLICATE join |
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A(n) __________________ is a type of JOIN operation that yields all rows with matching values in the join columns as well as all unmatched rows ( those without matching values in the join columns).
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[removed] |
d. DUPLICATE JOIN |
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Suppose that a PRODUCT table contains two attributes, PROD_CODE and VEND_CODE. Those two attributes have values of ABC, 125, DEF, 124, GHI, 124, and JKL, 123, respectively. The VENDOR table contains a single attribute, VEND_CODE, with values 123, 124, 125, and 126, respectively. (The VEND_CODE attribute in the PRODUCT table is a foreign key to the VEND_CODE in the VENDOR table.) Given that information, what would be the query output for a UNION query based on these two tables?
[removed] |
a. The query output will be: 123,124,125,126 |
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[removed] |
b. The query output will be: 125,124,124,123 |
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[removed] |
c. The query output will be: 125,124,123,126 |
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[removed] |
d. The query output will be: 123 |
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Triggers are critical to proper database operation and management in which of the following ways?
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a. add functionality by automating critical actions and providing appropriate warnings for remedial action. |
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b. used to enforce constraints that cannot be enforced at the DBMS design and implementation levels. |
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[removed] |
c. can be used to enforce referential integrity, to update table values, insert records in tables, and call other stored procedures. |
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[removed] |
d. All of these choices are correct.
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A(n) ________ is a virtual table based on a SELECT query.
Suppose that you have two tables, EMPLOYEE and EMPLOYEE_1. The EMPLOYEE table contains the records for three employees: Alice Cordoza, John Cretchakov, and Anne McDonald. The EMPLOYEE_1 table contains the records for employees John Cretchakov and Mary Chen. Given that information, what is the query output for the UNION ALL query?
[removed] |
a. The query output will be: Alice Cordoza, John Cretchakov, Anne McDonald and Mary Chen |
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[removed] |
b. The query output will be: John Cretchakov and Mary Chen |
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[removed] |
c. The query output will be: John Cretchakov |
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[removed] |
d. The query output will be: Alice Cordoza, John Cretchakov, Anne McDonald, John Cretchakov and Mary Chen |
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The ______________________ will yield all rows with matching values in the join columns, plus all of the unmatched rows from the right table.
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a. CENTER OUTER JOIN |
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[removed] |
b. RIGHT OUTER JOIN |
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[removed] |
c. LEFT OUTER JOIN |
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d. FULL OUTER JOIN |
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Use the following scenario for questions from this chapter:
You have been given a database for a small charity used to track donations made to it. It has the following structure:
and the following sample data in the tables:
Donor
Donor_Id |
Donor_
FirstName |
Donor_
LastName |
Donor_Address |
Donor_City |
Donor_State |
Donor_ZipCode |
Donor_Phone |
Donor_Email |
101 |
James |
James |
123 Mockingbird Place |
Peoria |
IL |
55556 |
555-555-2342 |
jj343434@somewhere.com |
175 |
Joseph |
Mays |
54321 7th St |
Atlantic City |
NJ |
15678 |
555-555-9877 |
jojo9@somewhere.com |
207 |
Susan |
Ames |
777 Main St |
Burlington |
KY |
41098 |
555-555-3478 |
amess@elsewhere.com |
303 |
Nancy |
Zornes |
P.O. Box 88776 |
Peoria |
IL |
55578-8776 |
555-555-1255 |
zornes98@nowhere.com |
ReceiptType
ReceiptType_Id |
ReceiptType_Description |
C |
Cash |
CK |
Check/Money Order |
CC |
Credit Card |
PD |
Payroll Deduction |
A |
Art / Collectible |
I |
In-kind |
Fund
Fund_Id |
Fund_Name |
G |
General Operation |
S |
Scholarship |
B |
Building Maintenance |
C |
Capital Campaign |
Receipt
Receipt_Id |
Donor_Id |
Receipt_Date |
ReceiptType_Id |
Fund_Id |
Receipt_Amount |
Receipt_Description |
1001 |
101 |
2015-01-05 |
CK |
G |
100 |
|
1002 |
207 |
2015-01-05 |
C |
S |
250 |
For: Virginia Wolfe Wilde |
1003 |
207 |
2015-01-05 |
C |
B |
100 |
|
1004 |
175 |
2015-01-06 |
CC |
G |
137.5 |
In Memory of Bob |
1005 |
101 |
2015-02-14 |
CK |
G |
100 |
|
1006 |
175 |
2015-02-20 |
A |
C |
15000000 |
Picasso Painting |
For reporting purposes the client would like you to create a temporary table called “FundSummary” that contains the fund id, donor id, the number of receipts (donations) made to the fund by a donor, and the total of the receipts and the donor. The new table from the sample data would look like:
|
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|
|
B |
207 |
1 |
100 |
C |
175 |
1 |
15000000 |
G |
101 |
2 |
200 |
G |
175 |
1 |
137.5 |
S |
207 |
1 |
250 |
Fill in the blanks of the SQL Statements:
Fund_Id VARCHAR(10) ,
Donor_id VARCHAR(10) ,
Count_Of_Receipts INTEGER,
Total_Receipts DECIMAL(10,2),
(Fund_Id, Donor_Id),
FOREIGN KEY (Donor_Id) REFERENCES ( ),
FOREIGN KEY ( ) REFERENCES (Fund_Id) );
INSERT INTO FundSummary
Fund_Id, Donor_Id, (Receipt_Id), ( )
FROM Receipt
Fund_Id, ;
Fill in the blanks with words that would best complete the passage.
donor_id
FundSummary
receipt_amount
(
not
null
select
sum
donor_id
primary
by
group
CREATE
key
donor
not
fund_id
fund
count
null
TABLE |
Use the following scenario for questions from this chapter:
You have been given a database for a small charity used to track donations made to it. It has the following structure:
and the following sample data in the tables:
Donor
Donor_Id |
Donor_
FirstName |
Donor_
LastName |
Donor_Address |
Donor_City |
Donor_State |
Donor_ZipCode |
Donor_Phone |
Donor_Email |
101 |
James |
James |
123 Mockingbird Place |
Peoria |
IL |
55556 |
555-555-2342 |
jj343434@somewhere.com |
175 |
Joseph |
Mays |
54321 7th St |
Atlantic City |
NJ |
15678 |
555-555-9877 |
jojo9@somewhere.com |
207 |
Susan |
Ames |
777 Main St |
Burlington |
KY |
41098 |
555-555-3478 |
amess@elsewhere.com |
303 |
Nancy |
Zornes |
P.O. Box 88776 |
Peoria |
IL |
55578-8776 |
555-555-1255 |
zornes98@nowhere.com |
ReceiptType
ReceiptType_Id |
ReceiptType_Description |
C |
Cash |
CK |
Check/Money Order |
CC |
Credit Card |
PD |
Payroll Deduction |
A |
Art / Collectible |
I |
In-kind |
Fund
Fund_Id |
Fund_Name |
G |
General Operation |
S |
Scholarship |
B |
Building Maintenance |
C |
Capital Campaign |
Receipt_Id |
Donor_Id |
Receipt_Date |
ReceiptType_Id |
Fund_Id |
Receipt_Amount |
Receipt_Description |
1001 |
101 |
2015-01-05 |
CK |
G |
100 |
|
1002 |
207 |
2015-01-05 |
C |
S |
250 |
For: Virginia Wolfe Wilde |
1003 |
207 |
2015-01-05 |
C |
B |
100 |
|
1004 |
175 |
2015-01-06 |
CC |
G |
137.5 |
In Memory of Bob |
1005 |
101 |
2015-02-14 |
CK |
G |
100 |
|
1006 |
175 |
2015-02-20 |
A |
C |
15000000 |
Picasso Painting |
Receipt
The client wants a listing of donor id, last name, first name, receipt date, type, and amount for all receipts greater than $100.00. The client wants the result sorted by donor last name, first name, and the donation date. The query result from the sample data would look like:
207 |
Ames |
Susan |
2015-01-05 |
C |
250 |
175 |
Mays |
Joseph |
2015-01-06 |
CC |
137.5 |
175 |
Mays |
Joseph |
2015-02-20 |
A |
15000000 |
Fill in the blanks of the SQL Statement:
Donor. , Donor_LastName, Donor_FirstName, Receipt_Date,
Receipt.ReceiptType_Id, Receipt_Amount
Receipt
Receipt.Donor_Id =
Receipt_Amount 100.00
Donor_LastName, Donor_FirstName, Receipt_Date;
Fill in the blanks with words that would best complete the passage.
from
>
donor.donor_id
select
donor
where
and
order
by
donor_id
,
The problems for this chapter use a database for a simple department store that sells items to customers and wants to keep track of the invoices, the selling price (if an item is on sale), and the sales tax (7%) to be collected on some items. Every customer and invoice are assigned unique numbers. All items have a Universal Product Code (UPC) number and bar-code assigned to each unique item. Food and non-carbonated beverages are not taxed, but clothing, home goods, and most other items are.
The structure of the tables are described in the following crows foot ERD:
Sample Data for the tables follow:
Customer
Customer_Id |
Customer_
FirstName |
Customer_
LastName |
Customer_
Address |
Customer_
City |
Customer_
State |
Customer_
ZipCode |
Customer_
Phone |
Customer_Email |
342 |
Linda |
Spangler |
2323 Roanoke Pk |
Floyd |
VA |
24987 |
555-555-5646 |
linda5646@nowhere.com |
505 |
Rodney |
Ray |
12399 27th Ave |
New York |
NY |
10097 |
555-555-0909 |
rayray7@somewhere.com |
776 |
Nancy |
Reno |
P.O.Box 98 |
Carter City |
KY |
41155 |
555-555-2342 |
puppylove8@elsewhere.com |
987 |
Gustov |
Jones |
333 East Main St |
Jamestown |
VA |
23099 |
555-555-9876 |
gustov99@somewhere.com |
ItemType
ItemType_Id |
ItemType_Description |
W |
Woman’s Clothing |
M |
Men’s Clothing |
WA |
Woman’s Accessories |
MA |
Men’s Accessories |
A |
General Accessories |
O |
Other |
ItemSize
ItemSize_Id |
ItemSize_Description |
XS |
Extra Small |
S |
Small |
M |
Medium |
L |
Large |
XL |
Extra Large |
Item
UPC |
Item_Description |
ItemType_Id |
ItemSize_Id |
Item_Price |
Item_Taxable |
012345234569 |
Cream Blouse |
W |
S |
29.95 |
1 |
012345234576 |
Cream Blouse |
W |
M |
29.95 |
1 |
012345234588 |
Cream Blouse |
W |
L |
29.95 |
1 |
012345234590 |
Cream Blouse |
W |
XL |
29.95 |
1 |
012345234468 |
Blue Blouse |
W |
S |
29.95 |
1 |
012345234475 |
Blue Blouse |
W |
M |
29.95 |
1 |
012345234491 |
Blue Blouse |
W |
XL |
29.95 |
1 |
012345224889 |
12 Inch Pearl Necklace |
WA |
|
345.95 |
1 |
012345224126 |
10 Inch Pearl Necklace |
WA |
|
298.95 |
1 |
012345334678 |
Explorer Cargo Shorts |
M |
S |
33.45 |
1 |
012345334734 |
Explorer Cargo Shorts |
M |
M |
33.45 |
1 |
012345334795 |
Explorer Cargo Shorts |
M |
L |
33.45 |
1 |
012345334889 |
Explorer Cargo Shorts |
M |
XL |
33.45 |
1 |
012345335101 |
Pink Silk Tie |
MA |
|
67.55 |
1 |
012345335303 |
Pink and Green Silk Tie |
MA |
|
67.55 |
1 |
012345999001 |
Yummy Bottled Water |
O |
|
1.29 |
0 |
Invoice
Invoice_Number |
Customer_Id |
Invoice_Date |
Invoice_Taxable |
Invoice_NonTaxable |
Invoice_SalesTax |
Invoice_Total |
10101 |
987 |
2015-07-27 |
29.95 |
2.58 |
2.1 |
34.63 |
10102 |
505 |
2015-07-27 |
33.45 |
0 |
2.34 |
35.79 |
10107 |
505 |
2015-07-28 |
59.99 |
1.29 |
4.2 |
65.48 |
10111 |
342 |
2015-07-28 |
262.89 |
0 |
18.4 |
281.29 |
InvoiceDetail
Invoice_Number |
UPC |
Detail_Quantity |
Detail_RegularPrice |
Detail_SellingPrice |
10101 |
012345334795 |
1 |
33.45 |
29.95 |
10101 |
012345999001 |
2 |
1.29 |
1.29 |
10102 |
012345334889 |
1 |
33.45 |
33.45 |
10107 |
012345335303 |
1 |
67.55 |
59.99 |
10107 |
012345999001 |
1 |
1.29 |
1.29 |
10111 |
012345234576 |
1 |
29.95 |
29.95 |
10111 |
012345234475 |
1 |
29.95 |
29.95 |
10111 |
012345224126 |
1 |
298.95 |
202.99 |
Suppose that we have a second table with vendor information (sample is below) in it and that we want to create a single telephone directory with both vendor and customer information in it.
Vendor_Id |
Vendor_CompanyName |
Vendor_Address |
Vendor_City |
Vendor_State |
Vendor_ZipCode |
Vendor_Phone |
Vendor_Email |
101 |
QRS Importers |
12345 Dock St |
San Fransisco |
CA |
97654 |
555-544-4444 |
bob@importeverythingsf.com |
505 |
ABC Supply |
505 Euclid Ave |
Lexington |
KY |
40505 |
555-505-0505 |
sales@abcsupplylex.com |
The phone directory should contain the state, a name column with either the customer last name and first name concatenated with a comma or the vendor company name, city, and phone number. Output should be sorted by state then by name. Your results should look like:
State |
Name |
City |
Phone |
CA |
QRS Importers |
San Fransisco |
555-544-4444 |
KY |
ABC Supply |
Lexington |
555-505-0505 |
KY |
Reno, Nancy |
Carter City |
555-555-2342 |
NY |
Ray, Rodney |
New York |
555-555-0909 |
VA |
Jones, Gustov |
Jamestown |
555-555-9876 |
VA |
Spangler, Linda |
Floyd |
555-555-5646 |
Fill in the blanks (remember a blank, drop “blank” as answer)
SELECT , , ,
FROM ( SELECT || ‘, ‘ || Customer_FirstName AS Name,
Customer_City , Customer_State AS State, Customer_Phone AS Phone
FROM Customer
SELECT Vendor_CompanyName AS Name,
Vendor_City AS City, Vendor_State AS State, Vendor_Phone AS Phone
FROM Vendor )
State, Name;
Fill in the blanks with words that would best complete the passage.
blank
Phone
city
City
Customer_LastName
blank
Name
AS
BY
UNION
State
ORDER
The problems for this chapter use a database for a simple department store that sells items to customers and wants to keep track of the invoices, the selling price (if an item is on sale), and the sales tax (7%) to be collected on some items. Every customer and invoice are assigned unique numbers. All items have a Universal Product Code (UPC) number and bar-code assigned to each unique item. Food and non-carbonated beverages are not taxed, but clothing, home goods, and most other items are.
The structure of the tables are described in the following crows foot ERD:
Sample Data for the tables follow:
Customer
Customer_Id |
Customer_
FirstName |
Customer_
LastName |
Customer_
Address |
Customer_
City |
Customer_
State |
Customer_
ZipCode |
Customer_
Phone |
Customer_Email |
342 |
Linda |
Spangler |
2323 Roanoke Pk |
Floyd |
VA |
24987 |
555-555-5646 |
linda5646@nowhere.com |
505 |
Rodney |
Ray |
12399 27th Ave |
New York |
NY |
10097 |
555-555-0909 |
rayray7@somewhere.com |
776 |
Nancy |
Reno |
P.O.Box 98 |
Carter City |
KY |
41155 |
555-555-2342 |
puppylove8@elsewhere.com |
987 |
Gustov |
Jones |
333 East Main St |
Jamestown |
VA |
23099 |
555-555-9876 |
gustov99@somewhere.com |
ItemType
ItemType_Id |
ItemType_Description |
W |
Woman’s Clothing |
M |
Men’s Clothing |
WA |
Woman’s Accessories |
MA |
Men’s Accessories |
A |
General Accessories |
O |
Other |
ItemSize
ItemSize_Id |
ItemSize_Description |
XS |
Extra Small |
S |
Small |
M |
Medium |
L |
Large |
XL |
Extra Large |
Item
UPC |
Item_Description |
ItemType_Id |
ItemSize_Id |
Item_Price |
Item_Taxable |
012345234569 |
Cream Blouse |
W |
S |
29.95 |
1 |
012345234576 |
Cream Blouse |
W |
M |
29.95 |
1 |
012345234588 |
Cream Blouse |
W |
L |
29.95 |
1 |
012345234590 |
Cream Blouse |
W |
XL |
29.95 |
1 |
012345234468 |
Blue Blouse |
W |
S |
29.95 |
1 |
012345234475 |
Blue Blouse |
W |
M |
29.95 |
1 |
012345234491 |
Blue Blouse |
W |
XL |
29.95 |
1 |
012345224889 |
12 Inch Pearl Necklace |
WA |
|
345.95 |
1 |
012345224126 |
10 Inch Pearl Necklace |
WA |
|
298.95 |
1 |
012345334678 |
Explorer Cargo Shorts |
M |
S |
33.45 |
1 |
012345334734 |
Explorer Cargo Shorts |
M |
M |
33.45 |
1 |
012345334795 |
Explorer Cargo Shorts |
M |
L |
33.45 |
1 |
012345334889 |
Explorer Cargo Shorts |
M |
XL |
33.45 |
1 |
012345335101 |
Pink Silk Tie |
MA |
|
67.55 |
1 |
012345335303 |
Pink and Green Silk Tie |
MA |
|
67.55 |
1 |
012345999001 |
Yummy Bottled Water |
O |
|
1.29 |
0 |
Invoice
Invoice_Number |
Customer_Id |
Invoice_Date |
Invoice_Taxable |
Invoice_NonTaxable |
Invoice_SalesTax |
Invoice_Total |
10101 |
987 |
2015-07-27 |
29.95 |
2.58 |
2.1 |
34.63 |
10102 |
505 |
2015-07-27 |
33.45 |
0 |
2.34 |
35.79 |
10107 |
505 |
2015-07-28 |
59.99 |
1.29 |
4.2 |
65.48 |
10111 |
342 |
2015-07-28 |
262.89 |
0 |
18.4 |
281.29 |
InvoiceDetail
Invoice_Number |
UPC |
Detail_Quantity |
Detail_RegularPrice |
Detail_SellingPrice |
10101 |
012345334795 |
1 |
33.45 |
29.95 |
10101 |
012345999001 |
2 |
1.29 |
1.29 |
10102 |
012345334889 |
1 |
33.45 |
33.45 |
10107 |
012345335303 |
1 |
67.55 |
59.99 |
10107 |
012345999001 |
1 |
1.29 |
1.29 |
10111 |
012345234576 |
1 |
29.95 |
29.95 |
10111 |
012345234475 |
1 |
29.95 |
29.95 |
10111 |
012345224126 |
1 |
298.95 |
202.99 |
You have been tasked to generate a report from the database using a single SQL statement to do the following:
List all items with the number of invoices that the items have been on and the total of the sales of that item. Display in order by type, description, and size.
Your generated output should look like:
UPC |
Item_Description |
ItemType_Id |
ItemSize_Id |
Invoice_Count |
Total_Sales |
012345334795 |
Explorer Cargo Shorts |
M |
L |
1 |
1 |
012345334734 |
Explorer Cargo Shorts |
M |
M |
0 |
|
012345334678 |
Explorer Cargo Shorts |
M |
S |
0 |
|
012345334889 |
Explorer Cargo Shorts |
M |
XL |
1 |
1 |
012345335101 |
Pink Silk Tie |
MA |
|
0 |
|
012345335303 |
Pink and Green Silk Tie |
MA |
|
1 |
1 |
012345999001 |
Yummy Bottled Water |
O |
|
2 |
3 |
012345234475 |
Blue Blouse |
W |
M |
1 |
1 |
012345234468 |
Blue Blouse |
W |
S |
0 |
|
012345234491 |
Blue Blouse |
W |
XL |
0 |
|
012345234588 |
Cream Blouse |
W |
L |
0 |
|
012345234576 |
Cream Blouse |
W |
M |
1 |
1 |
012345234569 |
Cream Blouse |
W |
S |
0 |
|
012345234590 |
Cream Blouse |
W |
XL |
0 |
|
012345224126 |
10 Inch Pearl Necklace |
WA |
|
1 |
1 |
012345224889 |
12 Inch Pearl Necklace |
WA |
|
0 |
|
Fill in the blanks (remember a blank, drop “blank” as answer)
SELECT Item.UPC, Item.Item_Description, Item.ItemType_Id,
Item.ItemSize_Id, COUNT(Invoice.Invoice_Number) AS Invoice_Count,
SUM(InvoiceDetail.Detail_Quantity) AS Total_Sales
FROM item
InvoiceDetail ON item. = .UPC
Invoice ON .Invoice_Number = InvoiceDetail.
GROUP BY Item.UPC
ORDER BY Item.ItemType_id, Item.Item_Description, Item.ItemSize_Id;
Fill in the blanks with words that would best complete the passage.
InvoiceDetail
LEFT
JOIN
blank
UPC
LEFT
Invoice
Invoice_Number
JOIN
Which of the following is the data dictionary’s function in database design?
[removed] |
a. It makes it easier to check for the existence of synonyms and homonyms, to check whether all attributes exist to support required reports, to verify appropriate relationship representations, and so on. |
|
|
[removed] |
b. Its contents are both developed and used during the six DBLC phases. |
|
|
[removed] |
c. It provides a precise description of the characteristics of all the entities and attributes found within the database. |
|
|
[removed] |
d. All of these choices are correct. |
|
In the decentralized conceptual database design approach, the aggregation process requires the lead designer to assemble a single model where which of the following aggregation problems must be addressed?
|
[removed] |
b. entity subclasses |
|
|
[removed] |
c. conflicting object definitions |
|
|
[removed] |
d. All of these choices are correct. |
|
______________ design begins by identifying the different entity types and the definition of each entity’s attributes.
|
[removed] |
b. Over the top |
|
|
|
[removed] |
d. None of these choices are correct.
|
|
_______________ is the last stage in the database design process.
[removed] |
a. Conceptual design |
|
|
[removed] |
b. Database design |
|
|
[removed] |
c. Physical design |
|
|
[removed] |
d. Logical design |
|
Which conceptual database design is best suited to relatively small and simple databases that lend themselves well to a bird’s eye view of the entire database and may be designed by a single person or by a small and informally constituted design team?
[removed] |
a. Centralized database design |
|
|
[removed] |
b. Distributed database design |
|
|
[removed] |
c. Decentralized database design |
|
|
[removed] |
d. Top-down database design |
|
A(n) ________________________ is a system that provides for data collection, storage, and retrieval; facilitates the transformation of data into information; and manages both data and information. It is composed of hardware, the DBMS and other software, database(s), people, and procedures.
[removed] |
a. information system |
|
|
[removed] |
b. storage system |
|
|
[removed] |
c. software system |
|
|
[removed] |
d. database system |
|
____________are narrative descriptions of the business policies, procedures, or principles that are derived from a detailed description of operations.
[removed] |
a. Entity rules |
|
|
[removed] |
b. Database rules |
|
|
[removed] |
c. Attribute rules |
|
|
[removed] |
d. Business rules |
|
The DBLC is composed of _____ phases.
Business rules are particularly valuable to database designers, because they help define which of the following?
|
[removed] |
b. relationships |
|
|
|
[removed] |
d. All of these choices are correct. |
|
The _________________ goal is to design an enterprise-wide database that is based on a specific data model but independent of physical-level details.
[removed] |
a. conceptual design |
|
|
[removed] |
b. database design |
|
|
[removed] |
c. physical design |
|
|
[removed] |
d. logical design
|
|
Which of the following is NOT a step performed in the physical design stage in the database design process?
[removed] |
a. Validate the model integrity constraints |
|
|
[removed] |
b. Determine performance measurements |
|
|
[removed] |
c. Define integrity and security measures |
|
[removed] |
d. Define data storage organization |
|
|
|
|
|
Which of the following is established during the systems design phase, in which the designer completes the design of all required system processes?
[removed] |
a. The database schema |
|
|
[removed] |
b. The detailed system specifications |
|
|
[removed] |
c. The user interface |
|
|
[removed] |
d. None of these choices are correct. |
|
Which of the following is established during the systems design phase, in which the designer completes the design of all required system processes?
[removed] |
a. The database schema |
|
|
[removed] |
b. The detailed system specifications |
|
|
[removed] |
c. The user interface |
|
|
[removed] |
d. None of these choices are correct. |
|
The conceptual design is composed of _____ steps.
Ultimately, the purpose of an _____________________ is to facilitate good decision making by making relevant and timely information available to the decision makers.
[removed] |
a. information system |
|
|
[removed] |
b. database system |
|
|
[removed] |
c. software system |
|
|
[removed] |
d. storage system |
|
Which conceptual database design is best when company operations are spread across multiple operational sites or when the database has multiple entities that are subject to complex relations?
[removed] |
a. Distributed database design |
|
|
[removed] |
b. Top-down database design |
|
|
[removed] |
c. Centralized database design |
|
|
[removed] |
d. Decentralized database design |
|
SDLC is the acronym that is used to label the _______________________________.
[removed] |
a. System Design Life Cycle |
|
|
[removed] |
b. System Development Life Cycle |
|
|
[removed] |
c. Software Design Life Cycle |
|
|
[removed] |
d. Software Development Life Cycle
|
|
A(n) ______________________ backup of the database creates a backup of only those database objects that have changed since the last full backup.
[removed] |
a. differential |
|
|
|
|
|
Which of the following shows how systems analysis fits into a discussion about information systems?
[removed] |
a. By evaluating the existing system |
|
|
[removed] |
b. By developing a logical systems design |
|
|
[removed] |
c. By establishing end-user requirements |
|
|
[removed] |
d. All of these choices are correct. |
|
DBLC is the acronym that is used to label the _______________________________.
[removed] |
a. Database Life Cycle |
|
|
[removed] |
b. Development Logical Cycle |
|
|
[removed] |
c. Database Logical Cycle |
|
|
[removed] |
d. Development Life Cycle |
|
The SDLC is composed of _____ phases.
Which of the following is NOT a step performed in the logical design stage in the database design process?
[removed] |
a. Validate the model using normalization |
|
|
[removed] |
b. Validate the model using user requirements |
|
|
[removed] |
c. Validate the model integrity constraints |
|
|
[removed] |
d. None of these choices are correct. |
|
A(n) _____________ is the use of different names to identify the same object, such as an entity, an attribute, or a relationship.
Database design must yield a database that does which of the following?
[removed] |
a. does not fall prey to uncontrolled data duplication, thus preventing data anomalies and the attendant lack of data integrity. |
|
|
[removed] |
b. is efficient in its provision of data access. |
|
|
[removed] |
c. serves the needs of the information system. |
|
|
[removed] |
d. All of these choices are correct. |
|
__________ design first defines the required attributes and then groups the attributes to form entities.
|
|
[removed] |
c. Over the top |
|
|
[removed] |
d. None of these choices are correct. |
|
The ___________________ specifies that all the data defined in the data model are actually required to fit present and expected future data requirements.
[removed] |
a. completeness data rule |
|
|
[removed] |
b. maximum data rule |
|
|
[removed] |
c. multiple data rule |
|
|
[removed] |
d. minimal data rule |
|
Which of the following is NOT one of the six (6) steps identified as part of the ER model verification process?
[removed] |
a. Verify all processes against the system requirements |
|
|
[removed] |
b. Identify each module and its components |
|
|
[removed] |
c. Identify the ER model’s central entity |
|
|
[removed] |
d. Map the entity names to proper process names |
|
How many steps are required in the development of the conceptual model using an ER diagram?
Which of the following is NOT an important factor in the selection of a DBMS software product?
[removed] |
a. DBMS features and tools |
|
|
|
|
[removed] |
d. Number of employees
|
|
2.Each of the following activities are commonly performed during the implementation of the Database Life Cycle (DBLC). Fill in the blank, before each activity, with the phase number of the DBLS that this activity would normally be performed.
DBLC Task Numbers:
1. Database initial study
2. Database design
3. Implementation and loading
4. Testing and evaluation
5. Operation
6. Maintenance and evolution
[removed] Load the initial values into the tables
[removed] Finish user documentation
[removed] Adding additional tables, attributes, and indexes
[removed] Attempt to gain unauthorized access to the data
[removed] Interview management
[removed] Convert existing data
[removed] Study the competition’s database
[removed] Plan how to grant different levels of access to different user groups
[removed] Install the database
[removed] Train users
[removed] Changing constraints to match changes in business rules
[removed] Define budget and scope
[removed] Select a DBMS software solution
[removed] Draw a logical ERD
[removed] Performing software patches to the DBMS
[removed] Create the database
[removed] Understand how this database will connect to other databases in the organization
[removed] Develop a Conceptual Model
[removed] Make sure application software updates the database
[removed] Regular security audits
[removed] Define objectives
[removed] Create a detailed model that can be physically implement