Management Skills Application Exercise [ad_1] After reading Chapter 14, you will be able to answer the following question on p. 493: Many companies strive to design jobs that are intrinsically motivating. Visit several small and large company websites and search their career section. What job features related to motivation are highlighted? What […]
Management Skills Application Exercise Read More »
How do I find the constant term of a binomial expansion? [ad_1] The expansion of a binomial is given by : ##(x+y)^n=( (n) (0) )*x^n+( (n) (1) )*x^(n-1)*y^1+…+( (n) (k) )*x^(n-k)*y^k+…+( (n) (n) )*y^n = sum_(k=0)^n*( (n) (k) )*x^(n-k)*y^k ## where ##x y in RR## ##k n in NN## and ##( (n) (k) )## denotes
How do I find the constant term of a binomial expansion? Read More »
Need by tomorrow [ad_1] Best practices in organizational learning within health organizations. -Summarize the topic discuss how this topic applies specifically to an organization of your choice. Discuss how the topic can be used to achieve organizational goals and challenge the status quo. -Support your post with at least one peer-reviewed source using course readings
How do I find the magnitude and direction angle of the vector v =6i-6j? [ad_1] Magnitude = ##|6i-6j|=sqrt(6^2+(-6)^2)=sqrt(72)=6sqrt(2)## Angle = ##arctan(-6/6)=arctan(-1)=-pi/4=-45## If you draw this vector on the plane the x-y coordinate axis as (6-6) because ##i## is the unit vector in the x-direction and ##j## in the y-direction. Then pictorially it might seem easier.
How do I find the magnitude and direction angle of the vector v =6i-6j? Read More »